BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

(3^x) (4^y) (5^z) = 3,276,800,000

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760
by sanju09 » Mon Feb 21, 2011 1:01 am
For integers x, y, and z, if (3^x) (4^y) (5^z) = 3,276,800,000 and x + y + z = 15, what is the value of xy/z?
(A) undefined
(B) 0
(C) 3
(D) 5
(E) 15
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 586
Joined: Tue Jan 19, 2010 4:38 amFollowed by: 5 members
Thanked: 31 times
GMAT Score:730

by rohu27 » Mon Feb 21, 2011 1:13 am
B

the given number is not a multiple of 3. so x must be zero.
i guess this is one of those questioswhere extra info is given.

sanju09 wrote:For integers x, y, and z, if (3^x) (4^y) (5^z) = 3,276,800,000 and x + y + z = 15, what is the value of xy/z?
(A) undefined
(B) 0
(C) 3
(D) 5
(E) 15
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Tue Feb 08, 2011 8:55 pm
Location: Canada
Thanked: 7 times
GMAT Score:700

by BarryLi » Mon Feb 21, 2011 1:20 am
In addition to x being zero, I believe it should be confirmed that z != 0. This is done by working out by hand 4^y for some integer close to 32,768. This is because 32,768 is a power of 2.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 436
Joined: Tue Feb 08, 2011 3:07 amFollowed by: 6 members
Thanked: 72 times

by manpsingh87 » Mon Feb 21, 2011 1:20 am
sanju09 wrote:For integers x, y, and z, if (3^x) (4^y) (5^z) = 3,276,800,000 and x + y + z = 15, what is the value of xy/z?
(A) undefined
(B) 0
(C) 3
(D) 5
(E) 15
B
as the given number is not divisible by 3..!!!
O Excellence... my search for you is on... you can be far.. but not beyond my reach!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 586
Joined: Tue Jan 19, 2010 4:38 amFollowed by: 5 members
Thanked: 31 times
GMAT Score:730

by rohu27 » Mon Feb 21, 2011 1:27 am
guess thts implied. as we have zeros at the end. despite the fact tht 32768 is factor of 4, the zeros bring 5 into euation.

BarryLi wrote:In addition to x being zero, I believe it should be confirmed that z != 0. This is done by working out by hand 4^y for some integer close to 32,768. This is because 32,768 is a power of 2.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1