What is the number of the x-intercepts of y=x^4-3x^3+2x^2?

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[GMAT math practice question]

What is the number of the x-intercepts of y=x^4-3x^3+2x^2?

A. one
B. two
C. three
D. four
E. five
Source: — Problem Solving |

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by fskilnik@GMATH » Mon Feb 04, 2019 4:27 am
Max@Math Revolution wrote:[GMAT math practice question]

What is the number of the x-intercepts of y=x^4-3x^3+2x^2?

A. one
B. two
C. three
D. four
E. five
$$?\,\,\,:\,\,\,\# \,\,x\,\,\,{\rm{for}}\,\,\,\,{x^4} - 3{x^3} + 2{x^2} = 0\,\,\,\left( * \right)$$
$$\left( * \right)\,\,\,\,\, \Rightarrow \,\,\,0 = {x^2}\left( {{x^2} - 3x + 2} \right) = {x^2}\left( {x - 1} \right)\left( {x - 2} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,x = 0,1\,\,{\rm{or}}\,\,2$$

The correct answer is therefore (C).


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by Max@Math Revolution » Wed Feb 06, 2019 6:55 am
=>

y = x^4-3x^3+2x^2
=> y = x^2(x^2-3x+2)
=> y = x^2(x-1)(z-2)
The x-intercepts occur when y = 0. This occurs when x = 0, x = 1 and x = 2.
There are three x-intercepts.

Therefore, the answer is C.
Answer: C

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by Scott@TargetTestPrep » Wed Feb 06, 2019 6:22 pm
Max@Math Revolution wrote:[GMAT math practice question]

What is the number of the x-intercepts of y=x^4-3x^3+2x^2?

A. one
B. two
C. three
D. four
E. five
The number of the x-intercepts of a function is equivalent to the number of distinct zeros of the function. To determine the x-intercepts, we set the function equal to zero and solve for x:

x^4-3x^3+2x^2 = 0

x^2(x^2 - 3x + 2) = 0

x^2(x - 1)(x - 2) = 0

x = 0 or x = 1 or x = 2

We see that the function has three distinct zeros; thus, it has three x-intercepts.

Answer: C

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