Ans is Dakay wrote:I am going in circles on this one.
If x, y and z are positive integers and 3x=4y=7z, then the least possible value of x + y + z is
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
3x=t the x=t/3
4y=t then y=t/4
7z=t then z=t/7
x+y+z = t/3 + t/4 + t/7 = 61t/84
Since x,y, z are (+)ive integer, x+y+z should be a (+)ive integer
therefore for min value of x+y+z, t should be 84 and the min value is 61
Let me know if there is a simpler approach to this problem

















