BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

GMAT past paper - Ratio

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 54
Joined: Fri Aug 10, 2007 6:51 am

Re: GMAT past paper - Ratio

by veekay » Sat Aug 11, 2007 10:18 pm
akay wrote:I am going in circles on this one.

If x, y and z are positive integers and 3x=4y=7z, then the least possible value of x + y + z is

(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Ans is D


3x=t the x=t/3
4y=t then y=t/4
7z=t then z=t/7

x+y+z = t/3 + t/4 + t/7 = 61t/84
Since x,y, z are (+)ive integer, x+y+z should be a (+)ive integer

therefore for min value of x+y+z, t should be 84 and the min value is 61

Let me know if there is a simpler approach to this problem
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 22
Joined: Fri May 04, 2007 3:51 am

by krishnamurthyu » Sat Aug 11, 2007 11:53 pm
If x, y and z are positive integers and 3x=4y=7z, then the least possible value of x + y + z is

(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Given: 3x=4y=7z=A
LCM of 3,4,7 = 84 [ They are co-prime hence LCM= 3*4*7 ]
= 3*(4*7) = 4 *(3*7) = 7 (3*4)
x+y+z = (4*7) + (3*7) + (3*4)
=28 +21+12
=61
=D.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 53
Joined: Sun May 06, 2007 5:03 am

by akay » Sun Aug 12, 2007 5:33 am
tks krishnamurthyu & veekay appreciate your taking the time.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1