BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT past paper - Ratio

Expert replies
Source: — Problem Solving |

Re: GMAT past paper - Ratio

by veekay » Sat Aug 11, 2007 10:18 pm
akay wrote:I am going in circles on this one.

If x, y and z are positive integers and 3x=4y=7z, then the least possible value of x + y + z is

(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Ans is D


3x=t the x=t/3
4y=t then y=t/4
7z=t then z=t/7

x+y+z = t/3 + t/4 + t/7 = 61t/84
Since x,y, z are (+)ive integer, x+y+z should be a (+)ive integer

therefore for min value of x+y+z, t should be 84 and the min value is 61

Let me know if there is a simpler approach to this problem
Join the discussion

by krishnamurthyu » Sat Aug 11, 2007 11:53 pm
If x, y and z are positive integers and 3x=4y=7z, then the least possible value of x + y + z is

(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
Given: 3x=4y=7z=A
LCM of 3,4,7 = 84 [ They are co-prime hence LCM= 3*4*7 ]
= 3*(4*7) = 4 *(3*7) = 7 (3*4)
x+y+z = (4*7) + (3*7) + (3*4)
=28 +21+12
=61
=D.
Join the discussion

by akay » Sun Aug 12, 2007 5:33 am
tks krishnamurthyu & veekay appreciate your taking the time.
Join the discussion