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by shashank.ism » Tue Feb 09, 2010 1:13 pm
The perimeter of an isosceles triangle is A cm and each of the two equal sides is B cm longer than the third unequal side. Which of the following is the length of the equal sides?

(A - B)/3
A + A/B
(A+B)/3
A/3 = B
None of these
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by fibbonnaci » Tue Feb 09, 2010 10:59 pm
let the side of unequal length be X.
The equal sides are X+ B

perimeter => X+X+B+X+B = A

3X+2B= A
X= (A-2B)/3

length of the equal side= X+B
(A-2B)/3 + B => (A+B)/3

option C is my answer
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by ajith » Thu Feb 11, 2010 9:02 am
shashank.ism wrote:The perimeter of an isosceles triangle is A cm and each of the two equal sides is B cm longer than the third unequal side. Which of the following is the length of the equal sides?

(A - B)/3
A + A/B
(A+B)/3
A/3 = B
None of these
Say the length of unequal side be X, length of equal sides = X+B

2(X+B) + X = A
3X = A-2B

X = (A-2B)/3
Length of equal sides = X+B =(A-2B)/3 + B = (A+B)/3
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by komal » Tue Feb 16, 2010 10:12 am
shashank.ism wrote:The perimeter of an isosceles triangle is A cm and each of the two equal sides is B cm longer than the third unequal side. Which of the following is the length of the equal sides?

(A - B)/3
A + A/B
(A+B)/3
A/3 = B
None of these
Let equal sides = x cm ⇒ 3rd side = x - B cm
⇒ Perimeter A = x + x + (x - B) = 3x - B cm
⇒ x =
(A + B)/3 cm.
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