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Source: — Problem Solving |
Master | Next Rank: 500 Posts
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by Sher1 » Sun Aug 09, 2009 8:56 am
B

If the average length of 5 is 124, then total length is 620.

Median is 140 so the middle one is 140. To maximize the lowest, we have to minimize the others.

Lets say the pieces are 1,2,3,4,5

we know 3 is 140, 4 and 5 at the minimum will be 140 as well.

now

620-420 is the lenght of the shortest 2

they both can be 100 each for the constraints to hold.

So 100 is the ans
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by sbasha » Sun Aug 09, 2009 8:57 am
The total length of 5 pieces are : 124*5 = 620.

Median is 140 , so lets have it as : a+b+140+140+140 ( The position of “C” is 140 which is a median and added “d” and “e” as 140 as well to get “Maximum Possible Length “

The remaining lengths are : 620-420 = 200.

So length of the remaining are 200/2 = 100.

Thanks
Syed Basha
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