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Exponents question- difficult

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Source: — Data Sufficiency |
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by kmittal82 » Mon Mar 05, 2012 9:02 am
(1)
n = +- [ sqrt(2.89) x 10^5]

Ofcos, since k is positive, the negative root is eliminated, hence we are left with only 1 value for n

SUFFICIENT

(2)
Since k is an integer, only 1 value of k will satisfy the given inequality and will put n at 170,000.

SUFFICIENT

Hence (D)
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by pemdas » Mon Mar 05, 2012 9:20 am
HG10 wrote:If k is a positive integer and n = 1.7 x 10^k, what is the value of n?

1. n^2 = 2.89 x 10^10
2. 20,000 < n < 200,000

OA: D
clearly it's d
st(1) implies n^2=(1.7*10^5)^2 not usual |n|=|1.7*10^5| but straight n=1.7*10^5 because the right side of n always stays positive. Hence n=170,000

st(2) again one possibility exists for k=5 and 20,000 < n=170,000 < 200,000
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by Troika » Mon Mar 05, 2012 5:07 pm
@kmittal82 and pemdas: thank you for the helpful solutions!
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by killer1387 » Mon Mar 05, 2012 9:09 pm
HG10 wrote:If k is a positive integer and n = 1.7 x 10^k, what is the value of n?

1. n^2 = 2.89 x 10^10
2. 20,000 < n < 200,000

OA: D
1.
n^2= 1.7^2*10^10
sufficient i.e. n will be in +- form but n is positive

2.
for k =5 unique value
sufficient

hence D
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by Troika » Tue Mar 06, 2012 12:16 am
killer1387 wrote:
HG10 wrote:If k is a positive integer and n = 1.7 x 10^k, what is the value of n?

1. n^2 = 2.89 x 10^10
2. 20,000 < n < 200,000

OA: D
1.
n^2= 1.7^2*10^10
sufficient i.e. n will be in +- form but n is positive

2.
for k =5 unique value
sufficient

hence D
Thanks!
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