I am assuming the 3rd term is sqrt(3)+1
(sqrt2+1)(sqrt2-1)(sqrt3+1)(sqrt3-1)
Use (a+b) ( a-b) = a^2-b^2
a = sqrt2
b = 1
2 - 1 = 1
Use (a+b) ( a-b) = a^2-b^2
a = sqrt3
b = 1
3 - 1 = 2
So
1*2 = 2
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