Adding a few
SPACES and some
NICER NOTATION will make this question less ambiguous.
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j_shreyans wrote:The sum of the first n positive perfect squares, where n is a positive integer, is given by the formula n³/3 + cn² + n/6, where c is a constant. What is the sum of the first 15 positive perfect squares?
A)1010
B)1164
C)1240
D)1316
E)1476
OAC
Our first task is to determine the value of c.
So, let's use the fact that, when n = 1, the SUM of the first 1 perfect squares is 1.
So, when n = 1, n³/3 + cn² + n/6 = 1
Replace n with 1 to get: 1³/3 + c(1²) + 1/6 = 1
Simplify: 1/3 + c + 1/6 = 1
Solve:
c = 1/2
Great. The sum of the first n perfect squares = n³/3 +
(1/2)n² + n/6 = 1
To find the sum of the first 15 perfect squares, plug n =
15 into the formula.
We get:
15³/3 + (1/2)
15² +
15/6 = 1125 + 225/2 + 5/2
= 1125 + 230/2
= 1125 + 115
=
1240
=
C
Cheers,
Brent