4^17 - 2^28GMATJeff wrote:Can anyone help explain an easy solution to this problem?
1. What is the greatest Prime Factor of 4^17 - 2^28?
The answer is 7, but I'm not clear on how it is derived.
Thanks!
4^17 = 2^17 * 2^17 = 2^34
2^34 - 2^28 = 2^28 (2^6 -1)
2^6 = 64
2^28 (64-1) = 2^28 * 63 = 2^28 * 7 * 3 * 3
greatest prime factor = 7
Hope this helps.












