probability

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Atult718: Senior | Next Rank: 100 Posts; Posts: 38; Joined: Wed Mar 14, 2007 1:17 am

by Atult718 » Mon Jul 30, 2007 6:08 am

I think the way you would it is...

1st try probability = 1/5 + 0
2nd try = 1/5+ 0

1/5+1/5 = 2/5

Is this correct ? or there is another way to do this ?

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Source: Beat The GMAT — Problem Solving | Mon Jul 30, 2007 6:08 am

givemeanid: Master | Next Rank: 500 Posts; Posts: 277; Joined: Sun Jun 17, 2007 2:51 pmFollowed by: 1 member; Location: New York, NY; Thanked: 6 times

by givemeanid » Mon Jul 30, 2007 6:47 am

P(chosing spoiled apple)
= 1 - P(not chosing spoiled apple)
= 1 - P(first apple is good)*P(second apple is good)
= 1 - 4/5 * 3/4
= 1 - 3/5
= 2/5

So It Goes

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