If anyone can help with this challenging (at least for me) PS question it would be appreciated !!!
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https://www.beatthegmat.com/problem-218- ... 70299.html
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Hard PS question
Source: Beat The GMAT — Problem Solving |
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GMATGuruNY
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Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
The question rephrased:
T = list of 30 positive decimals
10 decimals are "even"
20 decimals are "odd"
1st decimal place even -> round up to integer
1st decimal place odd -> round down to integer
E = estimated sum of new integers
S = sum of T
Find E-S
Minimum 10 rounded up = add (10 * 0.2) = 2
Maximum 10 rounded up = add (10 * 0.8) = 8
Minimum 20 rounded down = subtract (20 * 0.1) = -2
The maximum 20 rounded down = subtract (20 * 0.9)= -1.8
[Mean = (2 + 8 -2 - 1.8)/4 = 6.2]
Answers A and B are beyond the minimum and maximum vales, so 6 is acceptable: answer B.
T = list of 30 positive decimals
10 decimals are "even"
20 decimals are "odd"
1st decimal place even -> round up to integer
1st decimal place odd -> round down to integer
E = estimated sum of new integers
S = sum of T
Find E-S
Minimum 10 rounded up = add (10 * 0.2) = 2
Maximum 10 rounded up = add (10 * 0.8) = 8
Minimum 20 rounded down = subtract (20 * 0.1) = -2
The maximum 20 rounded down = subtract (20 * 0.9)= -1.8
[Mean = (2 + 8 -2 - 1.8)/4 = 6.2]
Answers A and B are beyond the minimum and maximum vales, so 6 is acceptable: answer B.
