Funny one: Surely the option are only C and E;
I would say 0.6 x 0.8 = 0.42 thus SUFF
IMO C
19q16
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The answer is E; the probability that *both* occur is only equal to 0.6*0.8 if the two events are independent (and Saffa- 0.6*0.8 is 0.48, not 0.42
). Imagine the following problem:
Pick a random integer between 1 and 5 inclusive.
Let A be "the number is less than or equal to 4"
Let B be "the number is less than or equal to 3"
Clearly the probability that both A and B occur is 0.6, not 0.48.
Pick a random integer between 1 and 5 inclusive.
Let A be "the number is less than or equal to 4"
Let B be "the number is less than or equal to 3"
Clearly the probability that both A and B occur is 0.6, not 0.48.
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stubbornp
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Awsome explanation....tnx ian...Ian Stewart wrote:The answer is E; the probability that *both* occur is only equal to 0.6*0.8 if the two events are independent (and Saffa- 0.6*0.8 is 0.48, not 0.42). Imagine the following problem:
Pick a random integer between 1 and 5 inclusive.
Let A be "the number is less than or equal to 4"
Let B be "the number is less than or equal to 3"
Clearly the probability that both A and B occur is 0.6, not 0.48.












