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The arithmetic mean of set S is zero. If T = {2:22, 1:96, 1:

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by riteshpatnaik » Tue Jun 21, 2016 9:41 pm
Ian Stewart Vol 2 Q195

The arithmetic mean of set S is zero. If T = {2:22, 1:96, 1:68, 1:62, 1:94, 2:16}
is the subset of S consisting of all those elements in S which are more than two but less than three standard deviations away from the arithmetic mean of S, what could
be equal to the standard deviation of S?
A) 0.54
B) 0.77
C) 0.82
D) 0.97
E) 1.62

I am unable to solve this. Please help
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Source: — Problem Solving |

by [email protected] » Tue Jun 21, 2016 9:53 pm
Hi riteshpatnaik,

Are you actually studying for the GMAT? I ask because this question is not representative of the types of Standard Deviation questions that you'll see on the Official GMAT. If you are studying for the GMAT, you might want to invest in more representative practice materials.

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by Matt@VeritasPrep » Thu Jun 23, 2016 4:04 pm
This actually seems fine, assuming that T = {2.22, 1.96, 1.68, 1.62, 1.94, 2.16}, and is clearly within the scope of the GMAT.

Let's call d the standard deviation. We know the mean is zero, so using the least and greatest values in the set, we have

0 + 2d < 1.62 < 0 + 3d

and

0 + 2d < 2.22 < 0 + 3d

The first equation tells us that d < .81 < (3/2)d, so the standard deviation must be less than .81: eliminate C, D, and E.

The second equation tells us that (2/3)d < .74 < d, so the standard deviation must be greater than .54: eliminate A.

We're left with B, so that's the choice!
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by Matt@VeritasPrep » Thu Jun 23, 2016 4:05 pm
By the way, just Googled to find the text of the problem, and it seems like T was meant to be in ascending order: {-2.22, -1.96, -1.68, 1.62, 1.94, 2.16}. Happily enough, though the answer doesn't change, since the sign on the standard deviation doesn't matter.

Be careful to post the text properly in the future, though: it makes a huge difference.
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by DavidG@VeritasPrep » Fri Jun 24, 2016 7:48 am
See here for another good standard deviation question: https://www.beatthegmat.com/gmat-prep-qu ... 77848.html
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