What is the value of a + b?

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What is the value of a + b?

by Max@Math Revolution » Wed Oct 30, 2019 11:58 pm
[GMAT math practice question]

What is the value of a + b?

1) ax + by = 2(ax - by) - 3 = x + y + 7
2) x = 3, y = 1
Source: — Data Sufficiency |

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edited:

by deloitte247 » Sun Nov 03, 2019 8:35 am
Statement 1 => ax + by = 2 (ax - by) - 3 = x + y + 7
2 (ax - by) - 3 = x + y + 7
and ax + by = 2 (ax - by) - 3
Therefore, ax + by = x + y + 7
There are so many unknown variable so the value of a + b cannot be estimate.
Hence, statement 1 is INSUFFICIENT

Statement 2 => x = 3 y = 1
There is no reference to variable a or b. Hence, statement 2 is NOT SUFFICIENT.

Combining both statements together =>
Statement 1 => ax + by = x + y + 7
Statement 2 => x = 3 and y = 1
ax + by = x + y + 7
a (3) + b (1) = 3 + 1 + 7
3a + b = 11
$$\frac{3a}{3}=\frac{11-b}{3}$$
$$a=\frac{11-b}{3}$$

using 2(ax - by) - 3 = x + y + 7
$$2\left[3\left(\frac{11-b}{3}\right)-b\left(1\right)\right]-3=3+1+7$$
2 (11-b - b) - 3 = 11
2 (11 - 2b) - 3 = 11
22 - 4b - 3 = 11
- 4b + 19 = 11
- 4b = 11 - 19 = -8
$$b=\frac{-8}{-4}=2$$

If a= (11-b)/3; and b=2

$$Therefore,\ a+b=\frac{11-b}{3}+\frac{2}{1}=\frac{\left(11-2\right)}{3}+\frac{2}{1}$$
$$a+b=\frac{11-2}{3}+\frac{2}{1}$$
$$\frac{9}{3}+\frac{2}{1}\ \ \ \ divide\ 9\ by\ 3$$
$$=3+2\ \ \ a+b=5$$

Both statements combined together are SUFFICIENT
Answer= option C

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by Max@Math Revolution » Sun Nov 03, 2019 6:16 pm
=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

We have 4 variables (a, b, x and y). However, since both conditions have 4 equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Since x = 3 and y = 1, we have 3a + b = 2(3a - b) - 3 = 3+1+7 = 11.
Then we have 3a + b = 11 and 6a - 2b = 14 or 3a - b = 7.
When we add those equations we have 3a + b + 3a - b = 11 + 7, 6a = 18 or a = 3.
Then we have 3(3) + b = 11, 9 + b = 11 or b = 2.

Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.