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Source: — Data Sufficiency |
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by Jim@StratusPrep » Wed Oct 24, 2012 5:52 pm
The key is that these are similar triangles because angle PQR is a right angle.

Thus:

a/2 = 2/b

With a or b you can solve for the diameter.
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by \'manpreet singh » Wed Oct 24, 2012 9:26 pm
a2 + 4 =PQ2
b2 + 4=QR2

PR= sq.root(PQ2+QR2)
(a+b)2 =a2 +b2 +8

2ab=8
ab=4
anwer= D
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