gmat prep coordinat plane
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arzanr
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center is (3,2)
3 and 2 have to be the averages of the 3 vertices of the triangle.
therefore, given the vertices (0,0) and (6,0)
(0+6+x)/3 = 3
and
(0+0+y)/3 = 2
solve for x and y, and you will get (3,6)
3 and 2 have to be the averages of the 3 vertices of the triangle.
therefore, given the vertices (0,0) and (6,0)
(0+6+x)/3 = 3
and
(0+0+y)/3 = 2
solve for x and y, and you will get (3,6)
