If w, x, y, and z are integers such that w/x and y/z are integers, is w/x + y/z odd?
(1)wx + yz = odd
(2)wz + xy = odd
(1)wx + yz = odd
(2)wz + xy = odd
To find: is w/x + y/z odd
Statement 1: wx + yz = odd
E + O
O + E
For wx Even = w must be Even & x can be ODD or even
For wx Odd = w & x must be ODD
For yz Even = y must be Even & z can be even or Odd
For yz Odd = y & z must be Odd
So, w/x + y/z
==> (w/x) can be Even or Odd -- depending upon "x"
==> (y/z) can be Even or Odd -- depending upon "z"
INSUFFICIENT
Statement 2: wz + xy = odd
w/x + y/z = INT
(wz + xy)/xz = INT
(ODD)/(xz) = INT
that means (xz) must be ODD ==> X & Z must be ODD
Coming back to equation:
w(ODD) + (ODD)y = odd ==> Either w is EVEN or y
Therefore, we have three odd terms and 1 even term and in numerators we have w & y one Odd and other Even
So, EVEN + Odd Or Odd + EVen == ODD
SUFFICIENT
Answer [spoiler]{B}[/spoiler]
