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During a trip, F traveled x% of the total distance

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by vishal.pathak » Wed Mar 07, 2012 2:54 pm
During a trip, F traveled x% of the total distance at an avg speed of 40 km/hr and the rest of the distance at an avg of 60 km/hr. In terms of x, what was F's avg speed for the trip
a. (180-x)/2
b. (x+60)/4
c. (300-x)/5
d. 600/(115-x)
e. 12000/(x+200)
OA E
I tried to solve it using assumption. Please point out my mistake
Let the distance be 480 and let 25% (This is x) of 480 be traveled at 40km/hr and the rest at 60 km/hr
So dist traveled at 40 = 120. Therefore time = 3hrs
Dist traveled at 60 = 360. Therefore time = 6 hrs
Avg speed = 480/9 = 160/3
Then I put x = 25 in all options
My answer didn't match any of the choices.
E= 12000/(25+200) = 12000/225 = 800/9

Please help

Regards,
Vishal
Last edited by vishal.pathak on Thu Mar 08, 2012 8:34 am, edited 1 time in total.
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by Brent@GMATPrepNow » Wed Mar 07, 2012 5:45 pm
vishal.pathak wrote:During a trip, F traveled x% of the total distance at an avg speed of 40 km/hr and the rest of the distance at an avg of 60 km/hr. In terms of x, what was F's avg speed for the trip
a. (180-x)/2
b. (x+60)/4
c. (300-x)/5
d. 600/(115-x)
e. 12000/(x+200)
OA E
I tried to solve it using assumption. Please point out my mistake
Let the distance be 480 and let 25% (This is x) of 480 be traveled at 40km/hr and the rest at 60 km/hr
So dist traveled at 40 = 120. Therefore time = 3hrs
Dist traveled at 60 = 360. Therefore time = 6 hrs
Avg speed = 480/9 = 160/3
Then I put x = 25 in all options
My answer didn't match any of the choices.
[spoiler]E= 12000/(25+200) = 12000/225 = 800/9
[/spoiler]
Please help

Regards,
Vishal
Almost there, Vishal!
You had the correct answer right up until the end (see above, behind the spoiler).
To simplify 12000/225, we can first divide top and bottom by 25 to get: 480/9, which equals 160/3

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by vishal.pathak » Thu Mar 08, 2012 8:32 am
Brent@GMATPrepNow wrote:
vishal.pathak wrote:During a trip, F traveled x% of the total distance at an avg speed of 40 km/hr and the rest of the distance at an avg of 60 km/hr. In terms of x, what was F's avg speed for the trip
a. (180-x)/2
b. (x+60)/4
c. (300-x)/5
d. 600/(115-x)
e. 12000/(x+200)
OA E
I tried to solve it using assumption. Please point out my mistake
Let the distance be 480 and let 25% (This is x) of 480 be traveled at 40km/hr and the rest at 60 km/hr
So dist traveled at 40 = 120. Therefore time = 3hrs
Dist traveled at 60 = 360. Therefore time = 6 hrs
Avg speed = 480/9 = 160/3
Then I put x = 25 in all options
My answer didn't match any of the choices.
[spoiler]E= 12000/(25+200) = 12000/225 = 800/9
[/spoiler]
Please help

Regards,
Vishal
Almost there, Vishal!
You had the correct answer right up until the end (see above, behind the spoiler).
To simplify 12000/225, we can first divide top and bottom by 25 to get: 480/9, which equals 160/3

Cheers,
Brent
I am very very stupid. I wish that I dont make such mistakes in the exam. Thanks for your help Brent

Regards,
Vishal
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Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
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Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Thu Mar 08, 2012 8:36 am
vishal.pathak wrote: I am very very stupid. I wish that I dont make such mistakes in the exam. Thanks for your help Brent
Regards,
Vishal
This is the best time to make silly mistakes. You can get them all out of your system before test day :-)

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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