Is m+z > 0?
(1) m-3z > 0
(2) 4z-m > 0
Statement 1: m > 3z.
m and z could both be positive, m and z could both be negative.
Insufficient.
Statement 2: m < 4z
m and z could both be positive, m and z could both be negative.
Insufficient.
Statements 1 and 2 combined:
Linking the inequalities, we get:
3z < m < 4z
3z < 4z.
0 < z.
Since z is positive, we know that m -- which is between 3z and 4z -- also is positive.
Thus, m+z > 0.
Sufficient.
The correct answer is
C.
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