BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

ds Q

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 371
Joined: Tue Apr 29, 2008 10:16 amFollowed by: 1 member
Thanked: 6 times
by vaivish » Tue Aug 05, 2008 10:25 am
There are six cards numbered from 1 to 6 in a box. With replacement, a card is taken out from the box three times. If the sum of the three cards is 12, is the card numbered 5 taken out at least for once?
(1) All the cards taken out cannot be divisible by 3.
(2) Two of the cards had been taken out.


Oa is C[spoiler][/spoiler]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Senior | Next Rank: 100 Posts
Posts: 42
Joined: Tue Jun 17, 2008 1:18 pm
Thanked: 2 times

Re: ds Q

by kshin78 » Tue Aug 05, 2008 12:05 pm
vaivish wrote:There are six cards numbered from 1 to 6 in a box. With replacement, a card is taken out from the box three times. If the sum of the three cards is 12, is the card numbered 5 taken out at least for once?
(1) All the cards taken out cannot be divisible by 3.
(2) Two of the cards had been taken out.


Oa is C[spoiler][/spoiler]

1. Cannot be divisible by 3 ---> excludes 3 & 6, leaving 1, 2, 4, 5

With given information, it can be (4,4,4) or (5,5,2) therefore NOT SUFFICIENT.

2. two cards had been taken out.
Options: (3,3,6) or (5,5,2) therefore NOT SUFFICIENT.

3. Combined. looking at both options, it can't be 4,4,4 because only two identical cards had been taken out and 3,3,6 is divible by 3. Therefore, only option left is 5,5,2 which is SUFFICIENT.

Answer C.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 683
Joined: Tue Jul 22, 2008 1:58 pmFollowed by: 2 members
Location: Dubai
Thanked: 73 times

Re: ds Q

by mals24 » Sat Aug 09, 2008 1:03 pm
kshin78 wrote:
vaivish wrote:There are six cards numbered from 1 to 6 in a box. With replacement, a card is taken out from the box three times. If the sum of the three cards is 12, is the card numbered 5 taken out at least for once?
(1) All the cards taken out cannot be divisible by 3.
(2) Two of the cards had been taken out.


Oa is C[spoiler][/spoiler]

1. Cannot be divisible by 3 ---> excludes 3 & 6, leaving 1, 2, 4, 5

With given information, it can be (4,4,4) or (5,5,2) therefore NOT SUFFICIENT.

2. two cards had been taken out.
Options: (3,3,6) or (5,5,2) therefore NOT SUFFICIENT.

3. Combined. looking at both options, it can't be 4,4,4 because only two identical cards had been taken out and 3,3,6 is divible by 3. Therefore, only option left is 5,5,2 which is SUFFICIENT.

Answer C.
I have a doubt in your explanation:
why don't we include (4,4,4) in st 2. it just says that two cards had been taken out it doesn't say which two cards had been taken out or whether two identical cards had been taken out.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1