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Newbie | Next Rank: 10 Posts
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Joined: Tue Aug 17, 2010 10:59 pm

by pseudotix » Wed Aug 25, 2010 7:22 am
You guys are getting into complex equations.. there's a simpler solution:

Day 1: 108 Pages
Day 2: 192 Pages
So 192-108=84 Pages more on day2 in 3 more hours

took 3 hours for 72 pages
so
in 1 hour it's 72/3=28

I have a question for which I'm looking shortest /simplest possible calculation:

Pump A, B & C operate at their respective constant rates. Pumps A & B, operating simultaneously, can fill a certain tank in 6/5 Hours; Pump A & C, operating simultaneously, can fill the tank in 3/2 hours; and Pumps B and C, operating simultaneously, can fill the tank in 2 Hours. How many hours does it take for Pump A, B & C, operating simultaneously, to fill the tank?
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Junior | Next Rank: 30 Posts
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by phillybeat » Wed Aug 25, 2010 9:48 pm
roh00kan wrote:Basically, 'x' - the time to read 108 pages is 27/7.

Since Brian needs additional 3 hours to read 192, the total time required for Brian to read 300 (108+192) is x+x+3 = 2x+3

Now 2x+3 is the time. We need the Avg rate. So we need to divide total pages Brian read with total time.

Avg Rate = 300/(2x+3)

Substitute for x

Rate = 300/(2*27/7 + 3) = 300*7/(54+21) = 4*7 = 28.

HPEngineer, your mistake was, you didn't consider the rate. If you are not familiar, write down the formula. R*T = Total. That helps, especially for word problems. So when you have an eq 2x+3 = 300, you are bound to make mistake.
When you write Avg R*total time = total pages read, you can avoid unnecessary mistakes.

cant we use this instead..
he needed 3 hrs to read extra 192-108 pages...
per hr reading speed is 84/3= 28..\is there anything wrong with this approach..
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