Is x > y?

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sanju09: GMAT Instructor; Posts: 3650; Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members; Location: India; Thanked: 267 times; GMAT Score:760

by sanju09 » Thu Mar 24, 2011 2:25 am

Is x > y?

(1) x/ (3 y) > 1/3.

(2) -x + p < -y + p.

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Source: Beat The GMAT — Data Sufficiency | Thu Mar 24, 2011 2:25 am

HSPA: Legendary Member; Posts: 1101; Joined: Fri Jan 28, 2011 7:26 amFollowed by: 13 members; Thanked: 47 times; GMAT Score:640

by HSPA » Thu Mar 24, 2011 5:30 am

B for me here

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nikhilsrl: Master | Next Rank: 500 Posts; Posts: 109; Joined: Mon Jan 10, 2011 3:05 amFollowed by: 7 members; Thanked: 8 times; GMAT Score:760

by nikhilsrl » Thu Mar 24, 2011 6:46 am

1) x/3y > 1/3 when evaluated this gives x>y - sufficient
2) -x+p< -y+p
adding -p on both sides -> -x < -y
multiplying by -1 on both sides -> x>y - sufficient

So D.

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kmittal82: Master | Next Rank: 500 Posts; Posts: 324; Joined: Mon Jul 05, 2010 6:44 amFollowed by: 3 members; Location: London; Thanked: 70 times

by kmittal82 » Thu Mar 24, 2011 7:20 am

IMHO, its (B)

(1)
Multiplying both sides by 3
x/y > 1

However, this doesn't mean x > y, since y could be negative

(2)
-x + p < -y + p
subtracting p from both
-x < -y
Multiplying by -1 both sides, signs change
x > y

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Night reader: Legendary Member; Posts: 1337; Joined: Sat Dec 27, 2008 6:29 pmFollowed by: 10 members; Thanked: 127 times

by Night reader » Thu Mar 24, 2011 10:59 am

x>y ?

st(1) we cannot multiply by 3y as we don't know if y (<), (>) 0, BUT we can multiply by 3 --> x/y >1.
It's possible to have x,y>0 OR x,y<0 for both variables (x and y) simultaneously, also |x|>|y|.
If x,y>0 then x>y. If x,y<0 x<y Not Sufficient;

st(2) -x+p < -y+p, -x < -y, x>y Sufficient

IOM B

sanju09 wrote:Is x > y?

(1) x/ (3 y) > 1/3.

(2) -x + p < -y + p.

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MAAJ: Master | Next Rank: 500 Posts; Posts: 243; Joined: Sun Jul 12, 2009 7:12 amFollowed by: 2 members; Location: Dominican Republic; Thanked: 31 times; GMAT Score:480

by MAAJ » Thu Mar 24, 2011 3:32 pm

IMO (B)

x/y > 1

IF +x/+y > 1 THEN +x > +y (e.g. 8/2 > 1)

IF -x/-y > 1 THEN -x < -y (e.g. -8/-2 > 1)

So Statement 1 is insufficient.

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