rjanardhanan wrote:If n is a positive number less than 15, is y greater than the average (arithmetic mean) of n and 15?
(1) On the number line, y is closer to 15 than it is to n
(2) y = 3n
0 < n < 15
Is y > (n+15)/2?
Part 1
The midpoint of n and 15 is (n+15)/2, wihch is the same as the arithmetic mean. Therefore, if y is closer to one or the other, we can safely answer the question. In this case, it is always TRUE.
SUFFICIENT.
Part 2
y = 3n
Plugging in...
3n > (n+15)/2 ?
5n > 15?
n > 3?
This is INSUFFICIENT, since the only known minimum constraint of n is 0.
A
