ktrout2020 wrote:If 0 < a < b, is c < 0?
(1) cb < ca
(2) a - b > c
Source: Veritas
0 < a < b implies the following:
b-a = bigger - smaller = POSITIVE
a-b = smaller - bigger = NEGATIVE
Statement 1:
cb - ca < 0
c(b-a) < 0
Implication:
c and b-a have DIFFERENT SIGNS.
Since b-a is positive, c must be negative.
SUFFICIENT.
Statement 2:
c < a-b
c < negative
Thus, c must be negative.
SUFFICIENT.
The correct answer is
D.
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