Any value for x that makes the denominator 0 will make the expression 2/((x-2)(x+1)) UNDEFINED
So if x = 2, the term (x-2) will become 0 or if x = -1, then term (x+1) will become zero. In either case, the denominator will reduce to 0
Ans D
Real numbers
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killerdrummer
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Because answer choices B & C say 2 only and -1 only respectively ..Clearly there are two unique values !
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