Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian...

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BTGmoderatorLU: Moderator; Posts: 2547; Joined: Sun Oct 15, 2017 1:50 pmFollowed by: 6 members

by BTGmoderatorLU » Sun Apr 18, 2021 8:08 am

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Source: Manhattan Prep

Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?

1) Brian’s walking speed is twice the difference between Ashok’s walking speed and his own

2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds

The OA is D

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Source: Beat The GMAT — Data Sufficiency | Sun Apr 18, 2021 8:08 am

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Re: Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian...

by Brent@GMATPrepNow » Fri May 21, 2021 7:23 am

BTGmoderatorLU wrote: ↑
Sun Apr 18, 2021 8:08 am
Source: Manhattan Prep

Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?

1) Brian’s walking speed is twice the difference between Ashok’s walking speed and his own

2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds

The OA is D

GIVEN: When the men start walking, Brian has a 30-mile lead

Let B = Brian's walking speed (in miles per hour)
Let A = Ashok's walking speed (in miles per hour)

Since Ashok's speed is greater than Brian's speed, the rate at which the gap shrinks = (A - B) miles per hour
For example, if A = 5 and B = 2, then the 30-mile gap will shrink at a rate of (5 - 2) mph.

time = distance/speed

So, time for 30-mile gap to shrink to zero = 30/(A - B)

Target question: How many miles will Brian walk before Ashok catches up with him?
This is a good candidate for rephrasing the target question.

distance = (speed)(time)
So, the distance Brian travels = (B)(30/(A - B))
Simplify to get: 30B/(A - B)

REPHRASED target question: What is the value of 30B/(A - B)?

Statement 1: Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.
We can write: B = 2(A - B)
Expand: B = 2A - 2B
This means: 3B = 2A
So: 3B/2 = A
Or we can say: 1.5B = A

Now take 30B/(A - B) and replace A with 1.5B to get: 30B/(1.5B - B)
Simplify: 30B/(0.5B)
Simplify: 30/0.5
Evaluate 60 (miles)
Perfect!! The answer to the REPHRASED target question is Brian will travel 60 miles
Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.
We can write: 5A = 3(A + B)
Expand: 5A = 3A + 3B
Rewrite as: 2A = 3B
We get: A = 3B/2 = 1.5B
At this point, we're at the same place we got to for statement 1.
So, since statement 1 is sufficient, we know that statement 2 is also sufficient.

Answer: D

Brent Hanneson - Creator of GMATPrepNow.com

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