Even/Odd Integers

This topic has expert replies
Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Mon Jan 07, 2013 8:58 pm

Even/Odd Integers

by bestofbala » Thu Mar 21, 2013 11:36 pm
For integers x and y is x+y Even?

(1) x*x - y*y is even
(2) x-y is even

I came across this question today and I am not convinced with the answer in the explanation. I want to check with you colleagues.
Source: — Data Sufficiency |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 511
Joined: Wed Aug 11, 2010 9:47 am
Location: Delhi, India
Thanked: 344 times
Followed by:86 members

by Anju@Gurome » Thu Mar 21, 2013 11:55 pm
bestofbala wrote:For integers x and y is x+y Even?

(1) x*x - y*y is even
(2) x-y is even
For any two integers x and y,
  • If (x - y) is even, then (x + y) is also even.
    If (x - y) is odd, then (x + y) is also odd.
Statement 1: x² - y² = (x - y)(x + y) is even.
Hence, either (x - y) or (x + y) or both are even.
In any case, (x + y) is even.

Sufficient

Statement 2: As (x - y) is even, (x + y) must be even too.

Sufficient

The correct answer is D.
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §

Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Mon Jan 07, 2013 8:58 pm

by bestofbala » Thu Mar 21, 2013 11:59 pm
Sorry, I am not understanding the explanation for Statement 1.

If (x+y)(x-y) is Even, 3 cases are possible: Both (x+y) and (x-y) are Even, (x+y) alone is Even and (x-y) alone is Even.

Isn't this giving a chance for (x+y) to be both Even and Odd. How come this information is sufficient to answer (x+y) is Even?
Last edited by bestofbala on Fri Mar 22, 2013 12:45 am, edited 1 time in total.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 511
Joined: Wed Aug 11, 2010 9:47 am
Location: Delhi, India
Thanked: 344 times
Followed by:86 members

by Anju@Gurome » Fri Mar 22, 2013 12:07 am
If (x - y) is even then (x + y) will be even and vice versa. This is true in general for any integers x and y.

Let's see why...
If (x - y) is even, then either of the following cases are possible...
  • 1. x and y both even
    2. x and y are both odd
In any of the above cases, (x + y) will be even as (even + even) = even and (odd + odd) = even.
bestofbala wrote:Sorry, I am not understanding the explanation for Statement 1.

If (x+y)(x-y) is Even, 3 cases are possible: Both (x+y) and (x-y) are Even, (x+y) alone is Even and (x-y) alone is Even.

Isn't this giving a chance for (x+y) to be both Even and Odd. How come this information is sufficient to answer (x+y) is Even?
You're correct that those 3 scenarios are possible (blue line).
In the first two cases, (x + y) is even so there should not be any confusion.
And in the third case, as (x - y) is even, (x + y) will be even too as I described previously. It is not possible that (x - y) is even but (x + y) is odd.

Hence, in all of the three possible cases, (x + y) will be even.

Hope that helps.
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §

Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Mon Jan 07, 2013 8:58 pm

by bestofbala » Fri Mar 22, 2013 12:53 am
Thanks, I now see that I've not seen enough to eliminate the impossible scenario.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Fri Mar 22, 2013 5:45 am
bestofbala wrote:For integers x and y is x+y Even?
(1) x*x - y*y is even
(2) x-y is even
Knowing the various rules (as Anju has demonstrated) is the best approach to these kinds of questions. However, if you don't know how to proceed in that manner, you can always test possible cases. This is more time-consuming, but still manageable within a 2-minute time frame.

For each statement, we'll examine the 4 different cases involving x and y. They are:
case a) x is even and y is even
case b) x is even and y is odd
case c) x is odd and y is even
case d) x is odd and y is odd

Target question: Is x+y even?

Statement 1: x^2 - y^2 is even
Let's examine x^2 - y^2 via the 4 cases. To do this, we'll plug in a 2 for an even number and a 1 for an odd number
case a) x is even and y is even: x^2 - y^2 = 2^2 - 2^2 = 0 (EVEN)
case b) x is even and y is odd: x^2 - y^2 = 2^2 - 1^2 = 3 (ODD)
case c) x is odd and y is even: x^2 - y^2 = 1^2 - 2^2 = -3 (ODD)
case d) x is odd and y is odd: x^2 - y^2 = 1^2 - 1^2 = 0 (EVEN)

Statement 1 tells us that x^2 - y^2 is EVEN. So, that means either case a is true or case d is true.
If case a is true, then x and y are both even, which means x+y is even.
If case d is true, then x and y are both odd, which means x+y is even.
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: x-y is even
Let's examine x-y via the 4 cases. To do this, we'll plug in a 2 for an even number and a 1 for an odd number
case a) x is even and y is even: x-y = 2-2 = 0 (EVEN)
case b) x is even and y is odd: x-y = 2-1 = 1 (ODD)
case c) x is odd and y is even: x-y = 1-2 = -1 (ODD)
case d) x is odd and y is odd: x-y = 1-1 = 0 (EVEN))

Statement 2 tells us that x-y is EVEN. So, that means either case a is true or case d is true.
If case a is true, then x and y are both even, which means x+y is even.
If case d is true, then x and y are both odd, which means x+y is even.
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = D

If you're interested, we have a free video that further explains this technique of testing cases: https://www.gmatprepnow.com/module/gmat- ... ies?id=839

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Fri Mar 22, 2013 6:07 am
bestofbala wrote:For integers x and y is x+y Even?

(1) x² - y² is even
(2) x-y is even
Every test-take should know the following:
even+even = even.
even-even = even.
odd+odd = even.
odd-odd = even.
These are the ONLY ways to get an even result.
If one of the terms is even while the other is odd, the resulting sum or difference will be ODD.

Statement 1: x² - y² is even
Case 1: x² - y² = even-even = even.
Options for x² and y²:
...(-8)², (-6)², (-4)², (-2)², 0², 2², 4², 6², 8²...
Thus, options for x and y:
-8,- 6, -4, -2, 0, 2, 4, 6, 8...
Since all of the values here are EVEN, x+y = even+even = even.

Case 2: x² - y² = odd-odd = even.
Options for x² and y²:
...(-7)², (-5)², (-3)², (-1)², 1², 3², 5², 7²...
Thus, options for x and y:
...-7, -5, -3, -1, 1, 3, 5, 7...
Since all of the values here are ODD, x+y = odd+odd = even.
SUFFICIENT.

Statement 2: x-y = even.
Case 1: x-y = even-even = even, in which case x+y = even+even = even.
Case 2: x-y = odd-odd = even, in which case x+y = odd+odd = even.
SUFFICIENT.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3