kdn508 wrote:If x and y are integers, is x/3 an integer?
STATEMENT 1:
x + 14 = 2y
STATEMENT 2:
(2y+1)/3 is an integer.
Question stem, rephrased: Is x divisible by 3?
Statement 1: x+14 = 2y
Since the question stem asks about x, rephrase statement 1 in terms of x:
x = 2y - 14
x = 2(y-7).
x will be a divisible by 3 if y-7 is divisible by 3.
Case 1: y-7 = 3
In this case, x = 2(y-7) = 2*3 = 6, which IS divisible by 3.
x will NOT be divisible by 3 if y-7 is NOT divisible by 3.
Case 2: y-7 = 1
In this case, x = 2(y-7) = 2*1 = 2, which is NOT divisible by 3.
INSUFFICIENT.
Statement 2: (2y+1)/3 is an integer
In other words, 2y+1 is a multiple of 3.
No information about x.
INSUFFICIENT.
Statements combined:
Statement 2 implies that 2y+1 is a multiple of 3.
Make a list of options and simplify:
2y+1 = 3, 6, 9, 12, 15, 18, 21...
Subtracting 1 from every value, we get:
2y = 2, 5, 8, 11, 14, 17, 20
Dividing every value by 2, we get:
y =
1, 5/2,
4, 11/2,
7, 17/2,
10...
Since y must be an integer, only the values in red are viable:
y = 1, 4, 7, 10...
Statement 1 implies that x will be divisible by 3 if y-7 is divisible by 3.
Testing our list of options for y, we get:
If y=1, then y-7 = -6.
If y=4, then y-7 = -3.
If y=7, then y-y = 0.
If y=10, then y-7 = 3.
In every case, y-7 is divisible by 3.
(Note that 0 is divisible by every integer, including 3.)
SUFFICIENT.
The correct answer is
C.
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