decimal number

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Source: — Data Sufficiency |

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by Domnu » Sat Jun 06, 2009 2:12 pm
We can have 16x to be an integer only for x = 1/2, 1/4, 1/8, 1/16, and of these, the first three have non-zero tenths digits while the latter has a tenths digit of 0, so (1) alone isn't sufficient.

However, for 8x to be an integer, x = 1/2, 1/4, 1/8, and all of these have non-zero tenths digits.

So, (2) alone is sufficient.
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by nervesofsteel » Sat Jun 06, 2009 10:55 pm
Domnu wrote:We can have 16x to be an integer only for x = 1/2, 1/4, 1/8, 1/16, and of these, the first three have non-zero tenths digits while the latter has a tenths digit of 0, so (1) alone isn't sufficient.

However, for 8x to be an integer, x = 1/2, 1/4, 1/8, and all of these have non-zero tenths digits.

So, (2) alone is sufficient.
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