Straight Math

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Straight Math

by syv11 » Sat Dec 01, 2007 6:01 pm
If -1/2<=x<=-1/3 and -1/4<=y<=-1/5 what is the minimum value of xy^2?

A -1/75
B -1/50
C -1/78
D -1/32
E -1/16

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by seekmba » Sun Dec 02, 2007 7:49 am
I think the ans is D =1/32

xy^2 = -1/2*-1/4^2 = -1/32
Whats the OA?