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DS Question

by GHong14 » Tue Dec 07, 2010 7:47 pm
Assuming K does not equal zero is 1/K>0

1. 1/(1-k)>0
2. 1/(1+k)>0

The answer is A. I thought it was E. Care to explain?
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by Rahul@gurome » Tue Dec 07, 2010 8:04 pm
Assuming K does not equal zero is 1/K>0

1. 1/(1-k)>0
2. 1/(1+k)>0

Now 1/k > 0, if k > 0 and 1/k < 0 if k <0.
Consider 1.
It means (1-k) >0 .
Or k < 1. So k>0 or k<0.
So it is not necessary, that 1/k > 0.
Next consider 2.
It means (1+k) > 0.
Or k > -1.So k < 0 or k > 0.
Again it is not necessary that 1/k > 0.
Next combine both 1. and 2.
So -1 <k <1.
Or k < 0 or k > 0.
So 1/k can be either > 0 or < 0.
Or 1. and 2. together are not sufficient.
The correct answer is E.
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