BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Kaplan 800 DS

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
User avatar
Legendary Member
Posts: 758
Joined: Sat Aug 29, 2009 9:32 pm
Location: Bangalore,India
Thanked: 67 times
Followed by:2 members

by sumanr84 » Mon Jul 19, 2010 12:38 am
Pdgmat2010 wrote:is p + q > r + s ?

stmt 1: p > r + s
stmt 2: q > r + s


pls pick nos while solving and explain!!

OA after a couple of posts
[spoiler]IMO : C[/spoiler]

St1 : p > r + s but we cannot be sure whether p + q > r + s, since q could be -ve as well, we don't know.
St2 : q > r + s but we cannot be sure whether p + q > r + s, since p could be -ve as well, we don't know.

Adding both the eqns we get,
p+q > 2 ( r+s) , hence definitely ( p+q) > ( r+s)

OA ?
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 176
Joined: Sun Feb 21, 2010 6:00 am
Thanked: 2 times
GMAT Score:710

by Pdgmat2010 » Mon Jul 19, 2010 12:43 am
i used the same logic.
consider p = q = -4

r = s = -3

stmt a : - 4 > -3 + -3
-4 > -6

stmt b: - 4 > -6

adding a and b
-4 -4 > -6 -6
-8 > -12

So , the answer should be C...

.dunno how Kaplan says its E
Top
User avatar
Legendary Member
Posts: 758
Joined: Sat Aug 29, 2009 9:32 pm
Location: Bangalore,India
Thanked: 67 times
Followed by:2 members

by sumanr84 » Mon Jul 19, 2010 1:49 am
I am 100% sure that C should be the answer. Let see if some expert just drop in with something unique otherwise..
Top
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Wed Aug 26, 2009 2:09 pm
Thanked: 1 times

by PRABHDEEP gill » Mon Jul 19, 2010 2:09 am
When you combine the two statements you get:

p+q>2(r+s)

This does not imply p+q is necessarily > than (r+s)

if both (p+q) and (r+s) are negative

eg (p+q) =-5 and (r+s)=-4

---> (p+q)> 2(r+s)--->-5>-8

BUT (p+q)<(r+s)

therefore (E)
Top
User avatar
Legendary Member
Posts: 758
Joined: Sat Aug 29, 2009 9:32 pm
Location: Bangalore,India
Thanked: 67 times
Followed by:2 members

by sumanr84 » Mon Jul 19, 2010 2:15 am
I got it now..;-)..i was really confused..thanks PRABHDEEP..

consider p = q = -4

r = s = -3

stmt a : - 4 > -3 + -3
-4 > -6

stmt b: - 4 > -6

adding a and b
-4 -4 > -6 -6

-8 > -12

but, -8 < -6 (r+s) hence, E
[edited my last post]
Top
User avatar
Legendary Member
Posts: 516
Joined: Mon Nov 02, 2009 6:42 am
Location: Mumbai
Thanked: 14 times
Followed by:1 members
GMAT Score:710

by ankurmit » Mon Jul 19, 2010 2:42 am
Thats a nice quistion
--------
Ankur mittal
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 176
Joined: Sun Feb 21, 2010 6:00 am
Thanked: 2 times
GMAT Score:710

by Pdgmat2010 » Mon Jul 19, 2010 3:05 am
thanks Prabhdeep , Suman for your replies..
got it now

so if i take p=-4 , q=-4 then p+q = -8
also if r=s=-3 then r+s =-6
p+q < r+s
although
p+q > 2(r+s)
guess the whole purpose of choosing -ve nos was to show that p+q can be less than r+s
that's what i missed.

Cheers,
Pd
PRABHDEEP gill wrote:When you combine the two statements you get:

p+q>2(r+s)

This does not imply p+q is necessarily > than (r+s)

if both (p+q) and (r+s) are negative

eg (p+q) =-5 and (r+s)=-4

---> (p+q)> 2(r+s)--->-5>-8

BUT (p+q)<(r+s)

therefore (E)
Top
Post new topic Post Reply
• Page 1 of 1