bhumika.k.shah wrote:45. If r is a constant and an = rn for all positive integers n,
for how many values of n is an < 100 ?
(1) a50 = 500
(2) a100 + a105 = 2,050
How can i find out the sequence???
sanju09 wrote:bhumika.k.shah wrote:45. If r is a constant and an = rn for all positive integers n,
for how many values of n is an < 100 ?
(1) a50 = 500
(2) a100 + a105 = 2,050
How can i find out the sequence???
Do you mean a^n = r^n? If yes, then please do the necessary edit all over.
OK....then it is an arithmetic progression with first term r and common difference r.bhumika.k.shah wrote:I actually dont know ... its not raised to - for sure!
its to the right hand side below the alphabet...
i dont even know whats it called as per the "math" way :-S
sanju09 wrote:bhumika.k.shah wrote:45. If r is a constant and an = rn for all positive integers n,
for how many values of n is an < 100 ?
(1) a50 = 500
(2) a100 + a105 = 2,050
How can i find out the sequence???
Do you mean a^n = r^n? If yes, then please do the necessary edit all over.
I actually dont know ... its not raised to - for sure!
its to the right hand side below the alphabet...
i dont even know whats it called as per the "math" way :-S
sanju09 wrote:OK....then it is an arithmetic progression with first term r and common difference r.bhumika.k.shah wrote:I actually dont know ... its not raised to - for sure!
its to the right hand side below the alphabet...
i dont even know whats it called as per the "math" way :-S
sanju09 wrote:bhumika.k.shah wrote:45. If r is a constant and an = rn for all positive integers n,
for how many values of n is an < 100 ?
(1) a50 = 500
(2) a100 + a105 = 2,050
How can i find out the sequence???
Do you mean a^n = r^n? If yes, then please do the necessary edit all over.
(1) a50 = r + 49 r = 500 (given), r = 10. Sufficient
(2) a100 + a105 = (r + 99 r) + (r + 104 r) = 2050 (given). r = 10. Sufficient
[spoiler]D[/spoiler]
