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Source: — Data Sufficiency |

by DanaJ » Fri Mar 13, 2009 8:14 am
1. 3r + 2s = 6 has number of possible solutions.
Take r = 1 and s = 1.5. In this case, 2r + 3s = 2 + 4.5 = 6.5, so 2r + 3s is not smaller than or equal to 6.
But if you take r = 2 and s = 0, then you get that 2r + 3s = 4, which is smaller than 6.
This is why 1 is not sufficient.

2. Again, you don't have enough info.
Take r = 1 and s = 1.5 and again, 2r + 3s = 6.5 > 6.
But take r = s = 1 and you get that 2r + 3s = 5 < 6.
This is why 2 is insufficient as well.

Taken together, the two stmts are of no use. The examples given in 1 satisfy stmt 2 as well, so they're enough to prove that E is the answer.
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by themaharaja1 » Fri Mar 13, 2009 9:57 am
i think each statement is sufficient as in both cases sum comes <= 6
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by Sumit69 » Sat Mar 28, 2009 2:19 am
It should be "b". Whats the OA
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