If vmt ≠ 0, is v^2m^3t^-4 > 0?

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Source: — Data Sufficiency |

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by cramya » Sat Mar 28, 2009 9:25 am
Given v is not 0, m is not 0 and t is not 0

We need to find the sign of

v^2*m^3 / t^4

We can see that all we need to determine is the sign of m since v and t when squared and when taken to the power 4 are alwasys positive.

Stmt I

m> v^2

v^2 is always positive so m is positive therefore v^2*m^3 / t^4 > 0

SUFF

Stmt II

m> t^4

t^4 is always positive so m is positive therefore v^2*m^3 / t^4 > 0

SUFF


Choose D

Regards,
CR