Is |x|=y-z
(1) x+y=z
(2) x<0
(1) x+y=z
(2) x<0
"Commitment is more than just wishing for the right conditions. Commitment is working with what you have."
We need to find if |x|= y-z.ikaplan wrote:Is |x|=y-z
(1) x+y=z
(2) x<0
We know that |x| >=0. We also know that if x<0, |x| = -x.
With that in mind, lets look at the statements.
1. x+y = z
=> - x = y-z
Now if x<0, |x|= y-z
But if x>0, |x|= z-y
Insufficient.
2. x<0
We know nothing about y,z. Insufficient.
Together we know x<0, therefore -x =|x|, but from 1 we know that -x = y-z, hence |x| = y-z. sufficient
Hence C is correct.
