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silivest60
- Junior | Next Rank: 30 Posts
- Posts: 29
- Joined: Sat Oct 27, 2007 9:49 pm
- Location: Vancouver, BC, Canada
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I think I have the solution on this, I just want to make sure that I'm not missing something....
I appreciate any feedback,
thanks a lot.
Here is how I would solve this:
the question is asking: What is n1? where n1-items Bob produced last week
Let n2-the number of items Bob produced this week
(1) says that last week: 480= (n1)x in case Bob produced less or equal to 36 items
or, 480=36x + (n1-36)1.5x, in case Bob produced more than 36 items.
Therefore not sufficient
(2) says that this week: 510 = (n1 + 2)x, in case of equal or less than 36 items,
or 510 = 36x + (n1 + 2 - 36) 1.5x, in case of over 36 items. Therefore not sufficient.
Combining (1) and (2), is still not sufficient because we don't know whether Bob produced more than 36 items or less. If we knew that than we would have had two equations with two unknown and the answer would have been (C). But in this case, we have two solutions, and therefore answer is (E)
I appreciate any feedback,
thanks a lot.
Here is how I would solve this:
the question is asking: What is n1? where n1-items Bob produced last week
Let n2-the number of items Bob produced this week
(1) says that last week: 480= (n1)x in case Bob produced less or equal to 36 items
or, 480=36x + (n1-36)1.5x, in case Bob produced more than 36 items.
Therefore not sufficient
(2) says that this week: 510 = (n1 + 2)x, in case of equal or less than 36 items,
or 510 = 36x + (n1 + 2 - 36) 1.5x, in case of over 36 items. Therefore not sufficient.
Combining (1) and (2), is still not sufficient because we don't know whether Bob produced more than 36 items or less. If we knew that than we would have had two equations with two unknown and the answer would have been (C). But in this case, we have two solutions, and therefore answer is (E)
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