Coin flip

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Coin flip

by isvas » Wed Mar 10, 2010 7:23 pm
DS:

Susan flipped a fair coin N times. What fraction of the flips came up heads?
(1) N = 24
(2) The number of flips that came up tails was N .

[spoiler]OA - B
To determine the fraction of the flips that came up heads, we would normally need to know the number of heads and the number of flips. Statement (1) gives us only part of the picture, the number of flips ( N ), so it is insufficient. Eliminate (A) and (D).

Statement (2) tells us the number of flips that came up tails, as a fraction of N. The only other option besides tails is heads, so we know the fraction of flips that came up heads. The value of N is then irrelevant. Statement (2) is sufficient[/spoiler]

How would I calculate the fraction?
Source: — Data Sufficiency |

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by mohit11 » Wed Mar 10, 2010 9:26 pm
Formula = P = Fav no of cases (F)/ Total no of cases (N).


1) N - 24 , P = F/N = F/24 ..insuff.


2) Number of heads = N - Number of tails. -- N-N = 0
In other words.. if you flip a coin (say) 2 Times and you get Tail both the times, so you did not get Head even a single time.

Hence B is the answer

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by isvas » Wed Mar 10, 2010 11:02 pm
My bad, (2) should have been (3/8)N
Not N

If Tails is (3/8)N, now would you determine Heads?

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by harsh.champ » Wed Mar 10, 2010 11:11 pm
Important point over here is that you do not suffer from statement carryover when gng frm statement 1 to statement 2.
Otherwise the answer can be marked "C".
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



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by isvas » Wed Mar 10, 2010 11:47 pm
I still didnt get it
if Tails is (3/8)N, how can I determine Heads

OA is B - so I should not carry over (1)

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by mohit11 » Wed Mar 10, 2010 11:54 pm
If no of Tails is 3/8N

Then Number of heads = N - 3/8 N

Hence B is sufficient.

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by isvas » Wed Mar 10, 2010 11:57 pm
gosh.. I missed the Q "fraction of"....
thats 5/8th of N :)

SILLY mistake

thanks guys