Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and equations ensures a solution.
#m = ((m!)!). lf m is a positive integer, what is the
value of m ?
(1) 2! = (m - 1)!
(2) #m is six times the value of 5!
==> In the original condition we have 1 variable (m) and we need 1 equation to match the number of variables and equations. Since we have 1 each in 1) and 2), D is likely the answer.
In actual calculation,
In case of 1), 2=m-1, m=3 sufficient and in case of 2), (m!)!=6(5!)=6!, m!=6=3*2*1, m=3 therefore is sufficient. Thus the answer is D.
For 95% of the questions that have 1) =2), D is the answer.
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