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for what you named the topic you post, it seems you could solve this data?tlt2372 wrote:
OA: D
How is this possible?
I think you mistyped something here.diebeatsthegmat wrote
<=> 8w+4x+2y+z=11
only w,x,x=1 and y=so so the 8*1+4*1+0+1=11
yep, i mistyped something but the solution was ok, wasnt it?limestone wrote:I think you mistyped something here.diebeatsthegmat wrote
<=> 8w+4x+2y+z=11
only w,x,x=1 and y=so so the 8*1+4*1+0+1=11
It must be 8*1 + 4*0 + 2*1 + 1 = 11
As x,y,z,w are either Zero or 1
and 8w+4x+2y+z=11
Assume that all are 1, then 8w+4x+2y+z = 15. We must try to let either x,y,z,w to be Zero to reduce the sum to 11. There's only 1 way, as 15 - 11 = 4, and ONLY x has "4" before it. Therefore the unique set must be: x = 0; z,y,w = 1.
The same approach for statement 2.
Thus D is the correct choice.
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