Given the linear equation y = kx + n, for what values of x will y < 0?
(1) n = 0
(2) k < 0
[spoiler]OA:C[/spoiler]
(1) n = 0
(2) k < 0
[spoiler]OA:C[/spoiler]
Restated: For what values of k is kx+n<0?
1. n=0. kx<0. solutions depend on the value of k. If k is positive, then all negative x values satisfy the inequality. If k is negative, all positive values satisfy the inequality, and if k=0, there is no solution. INSUFFICIENT.
2. k<0 kx<-n x>-n/k. So all values of x bigger than -n/k satisfy the inequality. However, we have no idea what n or k is, so we can't specify an exact range. INSUFFICIENT.
1&2: If we know that n=0, the inequality derived in the second statement will be true for x>0. SUFFICIENT.
