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by rkhicha » Wed Aug 18, 2010 12:15 am
What is the ratio of the average (arithmetic mean) height of students in class X to the average height of students in class Y?

(1) The average height of the students in class X is 120 centimeters.
(2) The average height of the students in class X and class Y combined is 126
centimeters.

Am not entirely sure about the answer in the book
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Source: — Data Sufficiency |
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by gmatmachoman » Wed Aug 18, 2010 12:53 am
Afrer rephrase : Ax / Ay = ?

St 1 : Ax= 120. No data abt Ay. Insufficient

St 2 : Application of weigted average concepts :

Aw = (Nx *Ax + Ny * Ay) /(Nx +Ny)

Aw = 126 . No idea abt Ax/Ay/Nx/Ny is given Insufficient

Combining st 1 & st 2 :

still we dont know Nx & Ny. So we cant find Ay

Hey Ax : Average of X, Ay :Average of Y Nx: Number of students in X, Ny> Number of students in Y

Pick E
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by kmittal82 » Wed Aug 18, 2010 12:59 am
Hi,

this question has been answered here as well, with a nice pointer for these types of questions:

https://www.beatthegmat.com/average-t23670.html
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by gmatmachoman » Wed Aug 18, 2010 1:17 am
kmittal82 wrote:Hi,

this question has been answered here as well, with a nice pointer for these types of questions:

https://www.beatthegmat.com/average-t23670.html
Okay Mittal, if the question would have asked what is the ratio of students in class & class Y what will be ur answer??
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by kmittal82 » Wed Aug 18, 2010 1:41 am
gmatmachoman wrote:
kmittal82 wrote:Hi,

this question has been answered here as well, with a nice pointer for these types of questions:

https://www.beatthegmat.com/average-t23670.html
Okay Mittal, if the question would have asked what is the ratio of students in class & class Y what will be ur answer??
I don't understand your question here gmatmachoman, could you repost it please?
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by ymach3 » Thu Aug 19, 2010 4:39 am
hi gmatmachoman


Okay Mittal, if the question would have asked what is the ratio of students in class & class Y what will be ur answer??

even then, the answer would be E because i dnt have S(y) in this case...


let me know if i am wrong.
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