mmslf75 wrote:arocks wrote:If x and y are positive, is 3x > 7y?
(1) x > y + 4
(2) -5x < -14y
I think the answer is B. The OA is D.
Stmt2
-5x<-14y or 5x>14y or 2.5x>7y
So stmt2 is suff.
stmt1 - Not sure how statement1 is useful?
Pls explain. Thanks.
x > y + 4
Put Y = 0,1,2...
x>4, x>5 , x>6..so on
Put y=0.5
x>4.5
We need to find out : (y/n)
is 3x > 7y?
x>(7/3)y ---- x>2.3 y
for y=0
x>0,
Stmt 1 says x>4 and querstion : Is x > 0... Ans YES
for y=0.5
x> (23/5)y
x> 4.6 y
Stmt 1 is x>4.5 and Question is X > 4.6 y
Answer NO
Therfore B
is the OA
Some creative math here!
Everyone is ok with (2), so let's just focus on (1).
We know that x and y are both positive, so we can only select positive values (i.e. not y=0).
We also know that x > y + 4
We want to know whether 3x > 7y.
Let's try a really small y and a really big y and see if it matters.
If y = 1, then x > 5. Let's make x as small as possible, 5.000001.
Is 3(5.0000001) > 7(1)? YES.
If y = 1000, then x > 1004. Let's make x as small as possible, 1004.0000001.
Is 3(1004.000001) > 7(1000)? NO.
Since (1) can produce both a YES and a NO, it's insufficient.