Using A : magnitude of x is either 10 or 2.5 [insufficient]
using B : magnitude of x can be 4,5 or more [insufficeitn]
Combining:
magnitude of x is 10
IMO C
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
ds:is x^2>5^2?
Source: Beat The GMAT — Data Sufficiency |
First take: 640 (50M, 27V) - RC needs 300% improvement
Second take: coming soon..
Regards,
HSPA.
Second take: coming soon..
Regards,
HSPA.
from 1st we get to know that x<5
from second we know that x>3 and x<-3
when we combine we get to know the range of x i.e -5<x<-3 and 3<x<5
thus NO
imo c
is this correct?
from second we know that x>3 and x<-3
when we combine we get to know the range of x i.e -5<x<-3 and 3<x<5
thus NO
imo c
is this correct?
Just to add to it, x can also be -4, -5, -6 ..HSPA wrote:using B : magnitude of x can be 4,5 or more [insufficeitn]
@Arjunshn, HSPA has describe it nice.
Hope it helps.
Regards,
Pranay
Pranay
I am not sure how you concluded x<5 from option 1.
My approach was to square on both sides to obtain a qudratic equation of x.
Then solve for x to get 5/2 and -10.
My approach was to square on both sides to obtain a qudratic equation of x.
Then solve for x to get 5/2 and -10.
Regards,
Pranay
Pranay
i took three intervals for the 1st equation x<-5, -5<x<5 and x>5
when u put the values on the number line only first two satisfy thus x<5
when u put the values on the number line only first two satisfy thus x<5
The two scenario approach is useful for equations using absolute values.arjunshn wrote:from 1st we get to know that x<5
from second we know that x>3 and x<-3
when we combine we get to know the range of x i.e -5<x<-3 and 3<x<5
thus NO
imo c
is this correct?
The equation has two solutions, which can be found using the two scenarios:
scenario 1: Copy the equation as is, without the absolute value. Solve.
X -5 = 3(X + 5)
x-5 = 3x+15
-5-15 = 3x-x
-20 = 2x
-10=x
Scenario 2: copy the equation without the absolute value sign, but put a (-) minus sign on one the right side.
X -5 = -3(X + 5)
x-5 = -3x-15
2x = -10
x=-2.5
As a final step for the two scenario approach, check your work by plugging in both values into the original equation |X -5| = 3 |X + 5| to see that the equation is indeed satisfied for both values:
x=-10 |-10 -5| = 3 |-10 + 5|
|-15| = 3|-5|
15 is indeed equal to 3*5.
x=-2.5 |-2.5 -5| = 3 |-2.5 + 5|
|-7.5| = 3|-2.5|
7.5 is indeed equal to 3*2.5.
So both of these values satisfy the equation, and are thus the solutions of x.
Alone, this is insufficient to answer the question: For x^2 to be greater than 5^2, x must be either >5 or smaller than -5.
-10 is smaller than -5, so the answer here is YES.
-2.5 is greater than -5, so the answer is NO.
Stat. (2) is insufficient for the same reasoning: it is possible to find examples that are both within and outside the required ranges.
combined, only x=-10 satisfies Stat. (2)'s requirements, so the answer to the question is a definite YES. Answer is C.
Taking into account that |a-b| = dist(a,b) for any two real numbers a and b (where dist means the distance in the real number line), please note that:arjunshn wrote:Is X^2 > 5^2 ?
1) |X -5| = 3 |X + 5|
2) |X| > 3
The question may be rephrased as: |x| > 5, that is, is dist(x, origin) greater than 5?
(1) dist(x,5) = 3*dist(x, -5)
Please note (diagram follows) that there are ONLY TWO points (real numbers) satisfying this statement, one of them certainly answering the question in the affirmative, the other one in the negative.
From sttm (2) we must "take out" one of the (only two) possibilities allowed by sttm (1), therefore we are done.
Regards,
Fabio.

Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
Its a great way to solve it faster..basically a shortcut or basic logic.
thanx alot for sharing it..
thank you
thanx alot for sharing it..
thank you
I´m glad you like it, arjunshn!arjunshn wrote:Its a great way to solve it faster..basically a shortcut or basic logic.
thanx alot for sharing it..
thank you
Cheers, Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br












