varun289 wrote:A car dealership carries only sedans and SUVs, and on Tuesday it sold 1/6 of the sedans that it had in stock at the beginning of the day. If no new inventory arrived at any point on Tuesday, and the only change in inventory was that some vehicles were sold, did the dealership have more than 100 vehicles in inventory at the beginning of the day Tuesday?
(1) By the end of the day, the dealership had sold 8/9 as many sedans as SUVs.
(2) The dealership sold 85% as many sedans on Tuesday as it did on Wednesday.
Statement 1: By the end of the day, the dealership had sold 8/9 as many sedans as SUVs.
Plug in the MINIMUM value for the number of SUVs sold.
Let SUVs sold = 9.
In this case, sedans sold = (8/9)8 = 8.
Since 1/6 of the TOTAL number of sedans were sold, we get:
8 = (1/6)(total sedans)
Total sedans = 48.
Here, the MINIMUM number of vehicles at the beginning of Tuesday = (SUVs sold) + (total sedans) = 9+48 = 57, which is LESS than 100.
But the total number of SUVs at the beginning of Tuesday could be ANY VALUE.
If at the start of Tuesday there were 1000 SUVs -- of which 9 were sold -- then the total number of vehicles at the beginning of Tuesday = (total SUVs) + (total sedans) = 1000 + 48 = 1048, which is GREATER than 100.
INSUFFICIENT.
Statement 2: The dealership sold 85% as many sedans on Tuesday as it did on Wednesday.
Since 85/100 = 17/20, we get:
(sedans sold on Tuesday) = (17/20)(sedans sold on Wednesday).
Plug in the MINIMUM value for the number of sedans sold on Wednesday.
Let sedans sold on Wednesday = 20.
In this case, sedans sold on Tuesday = (17/20)20 = 17.
Since 1/6 of the TOTAL number of sedans were sold, we get:
17 = (1/6)(total sedans)
Total sedans = 102.
Thus, the total number of vehicles at the beginning of Tuesday was greater than 100.
SUFFICIENT.
The correct answer is
B.
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