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sandeep_chhabra
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This prob is already discussed.
However,
From 1: 1/k-1 > 0 says : both numerator and denominator are positive.
So K-1 >0 => k>1 and from q we know k only could be 2 onwards so 1/K would be always greater than 0.
Sufficient.
From 2 : 1/k+1 >0 says : k+1 >0 here we can't limit K's value.
For example; K could be -1/2 then 1/k <0>0 so insufficient.












