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I wonder How B is the OA

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by vishubn » Fri Oct 03, 2008 10:51 pm
If n = 3k, is k an integer?
(1) n is an integer.
(2) n/6 is an integer.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Vishu
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Source: — Data Sufficiency |
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by jazzcat4u » Fri Oct 03, 2008 11:19 pm
If n = 3k, is k an integer?
(1) n is an integer.
(2) n/6 is an integer

statement (1),
if k = 2, then 3x2 = 6 = integer
if k = 1/3, then 3 x 1/3 = 1 which means that n = 1 = integer
since k could be 2 or 1/3, then this statement is not suff

statement (2), if n/6 = integer, then a good question to ask yourself is, what can n be? the only way for n/6 to be an integer is if n = an integer. so n must equal some multiple of 6. when you plug any multiple of 6 into the equation n=3k, then k = integer.
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by raju232007 » Fri Oct 03, 2008 11:30 pm
n/3=k

The question asked is whether k a integer or not

statement 1 tells that n is an integer...

Therefore n=1,2,3....etc
n/3=1/3,2/3,1...etc

So statement 1 is not sufficient

statement 2 tells that n/6 is an intege

Therefore n must be divisible by 6( i.e any multiple of 6 should satisfy this condition)
n=6,12,18,24...etc
n/6=1,2,3,4...etc

Therefore n/6 is an integer and hence statement 2 is sufficient..
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