It is max 2 min question.
first of all you should know that sum of angles of triangle = 180. and thus in triangle pqr,
qpr + pqr + prq = 180 and thus option A and B are same.
Thus answer is either D or E.
now we have to find prs - pqr.
in triangle prs, rps + prs = 90
and in triangle pqs, pqs + qps = 90. pqs = pqr. thus pqr + qps = 90.
also rps = qps - qpr.
Thus qps - qpr + prs = pqr + qps -> prs - pqr = qpr = 30
Sufficient
IMO D

agree with cans, both options are the same st(1)=st(2), hence d

we need to find prs-pqr=?

st(1) qpr=30`, pqr+prq=150` , pqr=150`-prq and prs-150`+prq=prs-pqr. Since prs+prq=180` we rewrite 180-150=prs-pqr=30 is Sufficient
st(2) pqr+prq=150`, the same as above Sufficient

Thanks everyone.... I agree now that it is around 2 min question....and I should have solved it,
But at times in exam like situation it gets tough to solve.
Thanks anyways...