DS: Distance/time/speed

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DS: Distance/time/speed

by haidgmat » Sun Sep 05, 2010 5:59 pm
A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at a constant rate of 20 miles per hour. The cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate. How many minutes must the cyclist wait until the hiker catches up?
a. 6 2/3
b. 15
c. 20
d. 25
e. 26 2/3

OA- C
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by Rahul@gurome » Sun Sep 05, 2010 7:23 pm
Solution:
In 5 minutes, the cyclist must have covered (5/60)*20 miles.
In 5 minutes, the hiker must have covered (5/60) * 4 miles.
So the distance between them after 5 minutes, when the cyclist stops is (5/60)*20 - (5/60) * 4 miles = (5/60) * 16 miles.
So the time taken by hiker to cover this distance is [(5/60) * 16]/4 = (20/60) hours = 20 minutes.

The correct answer is C.
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