Book got this problem wrong

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Book got this problem wrong

by Rudy414 » Fri Mar 22, 2013 2:53 pm
If x is even, and 90 (less than/equal to) x (less than/equal to) 100, what is the value of x?

1) x and x/2 have the same distinct prime factors

2) x/2 has two prime factors

The answer key says, and I quote verbatim, "...Statement 1 is not sufficient. Eliminate choices B, C, and E." And it says the answer is C. Clearly, something is wrong here.
Source: — Data Sufficiency |

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by Anju@Gurome » Fri Mar 22, 2013 3:05 pm
Rudy414 wrote:If x is even, and 90 ≤ x ≤ 100, what is the value of x?

1) x and x/2 have the same distinct prime factors
2) x/2 has two prime factors
Possible values of x are : 90, 92, 94, 96, 98, and 100

Statement 1: This means x must be divisible by 4
Hence, possible values of x are : 92, 96, and 100

Not sufficient

Statement 2: Possible values of x/2 are : 45, 46, 47, 48, 49, and 50
Now,
  • 45 = 3*3*5
    46 = 2*23
    47 = 47
    48 = 2*2*2*2*3
    49 = 7*7
    50 = 2*5*5
As x/2 has two prime factors, possible values of x/2 are : 46 and 49
Hence, possible values of x are : 92 and 98

Not sufficient

1 & 2 Together: Only possible value of x is 92

Sufficient

The correct answer is C.
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by Rudy414 » Sat Mar 23, 2013 5:42 am
For statement 1, can you explain why x must be divisible by 4? I don't quite understand how you reached that conclusion.

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by Anju@Gurome » Sat Mar 23, 2013 6:03 am
Rudy414 wrote:For statement 1, can you explain why x must be divisible by 4? I don't quite understand how you reached that conclusion.
As x is even, let us assume that x = 2*a*b*c*..., where a, b, c etc are prime factors of x.
So, x/2 = a*b*c*...

As x and x/2 have same distinct prime factors and 2 is a prime factor of x, 2 must be a prime factor of x/2 also. Hence, at least one of a, b, c etc must be equal to 2. Which in turn means x will be divisible by another 2, i.e. x is divisible by 4.

Hope that helps.
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